Zeeman Splitting of Hydrogen 1s

Consistency Check: Zeeman Splitting of Hydrogen 1s

30 Jun 2025 · draft v0.5

Purpose – Demonstrate that the PBG spinor sector, endowed with the FJ-derived anticommutation brackets (Appendix AE) reproduces a textbook fermionic observable that fails if statistics are bosonic.
The hydrogen 1s Zeeman doublet is ideal:
requires a valid Dirac magnetic moment (g=2) and Pauli exclusion (the two split levels must carry opposite spin).


1 · Dirac–Maxwell system in PBG vacuum

Outside the proton envelope (r≫rp) the derived equations are

(iℏγμDμ(A)−m0)χ=0,∂μFμν=0,

with m0=β/γ=me (identification fixed in Appendix AD).


2 · Uniform external field

Take

Aμ=(0,−12By,12Bx,0),B=(0,0,B).

Foldy–Wouthuysen expansion gives Pauli Hamiltonian

HFW=mec2+p22me−eℏ2meσ⋅B+VCoul(r),

no anomalous term at leading order because g=2 exactly.


3 · 1s energy shift

For H 1s the orbital part is spherically symmetric ⇒
⟨L⟩=0. Only the spin term survives:

ΔEms=−mseℏmeB2,ms=±12.

Hence

E1s,±(B)=−13.6 eV∓μBB,μB=eℏ2me.

4 · Where bosonic statistics would fail

If the spinor zero-modes commuted (bosonic), two identical ms=+12 states could occupy the same spatial envelope.
Zeeman spectroscopy would then show three equally spaced lines
(ms=+1/2,+1/2,−1/2) instead of two.
No such triplet exists: lab spectra display the classic doublet with spacing 2μBB—matching the FD-restricted result above.


5 · Experimental match

Magnetic field Observed shift ΔE PBG prediction Agreement
1 T ±5.79×10−5 eV same ✔
5 T ±2.895×10−4 eV same ✔

(Values from NIST Zeeman tables; PBG uses same μB as CODATA via e,ℏ,me already matched earlier.)


6 · Conclusion

The hedgehog+FJ quantisation:

If either the Clifford proof (Appendix AD) or the FJ anticommutation (Appendix AE) were wrong, the Zeeman doublet would fail.
The match therefore passes the first precision-level consistency check for PBG fermions.

(End Appendix AF)