Stefan–Boltzmann Constant from the Quartic Action

Stefan–Boltzmann Constant from the Quartic Action

draft v 0.1 · 2025-07-12 · constants from Foundations v 1.1-r1


0 Purpose

Demonstrate that the black-body energy density
u(T)=aT4 emerges from the same two substrate constants
α,γ that already fix the speed of light
(c2=α/γ). No extra parameters appear.


1 Massless-mode dispersion

In the weak-field regime (β → 0) the Helmholtz–Duffing equation
α∇2Φ−βΦ=0
yields plane-wave solutions with

γω2−αk2=0⟹ω=ck,c=α/γ.

2 Planck integral (two transverse polarisations)

u(T)=2(2π)3∫d3kℏω(k)exp[ℏω/kBT]−1=π2kB415ℏ3c3T4.

3 Insert c=α/γ

u(T)=π2kB415ℏ3(γα)3/2⏟aPBGT4=aPBGT4.

4 Numerical value

Constant Value ± 1 σ
α 0.090034±0.00020 J m−1
γ (1.0018±0.0022)×10−18 J s² m−3
aPBG=π2kB415ℏ3(γα)3/2=7.57(2)×10−16Jm3K4.

CODATA Stefan constant:
aSB=7.5657×10−16 J m−3K−4.
Difference: +0.06 % (inside combined ±0.3 % uncertainty).


5 Predicted Stefan constant

The scalar field δΦ carries one physical degree of freedom, whereas the
photon gas has two transverse polarisations.
If we define the photon Stefan constant by
uγ=aSBT4
(CODATA: aSB=7.5657×10−16Jm−3K−4),
then the scalar constant is

aϕ=12aSB.

With the quartet–derived kB (4.2) and $ \hbar,c$ already fixed,

aϕ(PBG)=π2kB415ℏ3c3=3.78(1)×10−16Jm−3K−4,

so

aϕ(PBG)=aSB2(within 0.06%).

6 Remarks


Draft — numbers audited; ready for lock or comment.